x^2-4x+4I=2

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Solution for x^2-4x+4I=2 equation: 


Simplifying
x2 + -4x + 4I = 2

Reorder the terms:
4I + -4x + x2 = 2

Solving
4I + -4x + x2 = 2

Solving for variable 'I'.

Move all terms containing I to the left, all other terms to the right.

Add '4x' to each side of the equation.
4I + -4x + 4x + x2 = 2 + 4x

Combine like terms: -4x + 4x = 0
4I + 0 + x2 = 2 + 4x
4I + x2 = 2 + 4x

Add '-1x2' to each side of the equation.
4I + x2 + -1x2 = 2 + 4x + -1x2

Combine like terms: x2 + -1x2 = 0
4I + 0 = 2 + 4x + -1x2
4I = 2 + 4x + -1x2

Divide each side by '4'.
I = 0.5 + x + -0.25x2

Simplifying
I = 0.5 + x + -0.25x2

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